Celina is a city in and the county seat of Mercer County, Ohio, United States. The population was 10,400 at the 2010 census. Celina is situated on the western shores of Grand Lake St. Marys.
James Watson Riley established Celina in 1834. The settlement was named after Salina, New York.
Celina is located at 40°33′5″N 84°34′12″W (40.551459, -84.570057), at an elevation of 886 feet (270 m). According to the United States Census Bureau, the city has a total area of 5.27 square miles (13.65 km²), of which 4.98 square miles (12.90 km²) is land and 0.29 square miles (0.75 km²) is water.
As of the census of 2010, there were 10,400 people, 4,264 households, and 2,791 families residing in the city. The population density was 2,087.9 people per square mile (906.2/km²). There were 4,841 housing units at an average density of 1,017.3 per square mile (392.8/km²). The racial makeup of the city was 94.9% White, 0.5% African American, 0.4% Native American, 1.2% Asian, 0.4% Pacific Islander. Hispanic or Latino of any race were 2.8% of the population.
There were 4,329 households of which 31.8% had children under the age of 18 living with them, 45.5% were married couples living together, 13.0% had a female householder with no husband present, and 35.5% were non-families. 30.7% of all households were made up of individuals and 27.8% had someone living alone who was 65 years of age or older. The average household size was 2.37 and the average family size was 2.94.
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